P = purple, pp = white. The offspring of a cross between two heterozygous purple-flowering plants (Pp × Pp) r

P = purple, pp = white. The offspring of a cross between two heterozygous purple-flowering plants (Pp × Pp) results in





a. all purple-flowered plants.



b. purple-flowered plants and white-flowered plants.



c. two types of white-flowered plants: PP and Pp.



d. all white-flowered plants.



e. all pink-flowered plants.

P = purple, pp = white. The offspring of a cross between two heterozygous purple-flowering plants (Pp × Pp) r
If we set up a punnet square, then we get:



___P__p

P PP Pp

p Pp pp



PP and Pp are purple flowered plants

pp is a white flowered plant



So we know it can't be a because we have white plants. B seems to work at this point. C can't be right because we know PP and Pp produce purple plants. Looking at D and E, we know they are wrong because we have purple flowers and no pink flowers. So the answers is . . .
Reply:Pardon my terminology, but look at your text book, dumbo. Think about it. If you have the question to list out in so specific of a form, it must have come from a text. The text will not require you to give an answer which they have not equipped you to do. Now in a Pp*Pp cross you can get_______



PP, Pp, Pp, and pp



Simple Punett square



Sorry for being so mean.
Reply:PP, Pp, Pp, pp. That would be b, c.
Reply:b.



PP = purple

Pp = purple

pP = purple

pp = white



Purple : white 3:1
Reply:Do you know how a Punnett square works? Look in your textbook.



P p

-----------------------

P | PP Pp

|

p | Pp pp



Resulting in a 25% chance of white-flowered plants and a 75% chance of purple ones. Therefore the answer is b. It can't be c. because a capital P means purple, so PP can't be a white-flowered plant.